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Question
boyles law states that the volume of a gas varies inversely with applied pressure. a helium balloon has a volume of 22 cubic meters at sea level where the air pressure is 1 atmosphere. the balloon is released and rises to a point where the air pressure is only 0.8 atmosphere. what is the volume at this height? ? cubic meters
Step1: Write the inverse - variation formula
Boyle's law is \(V_1P_1 = V_2P_2\), where \(V_1 = 22\) cubic meters, \(P_1 = 1\) atmosphere, and \(P_2=0.8\) atmosphere.
Step2: Solve for \(V_2\)
Substitute the values into the formula: \(22\times1=V_2\times0.8\). Then \(V_2=\frac{22\times1}{0.8}\).
Calculate \(\frac{22}{0.8}=\frac{220}{8} = 27.5\).
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\(27.5\)