Question

bob puts 200 grams of ice into a pitcher with 900 grams of water. he gets distracted and comes back later to find that the ice has melted in the water. how many grams of water does bob now have in the pitcher?

Explanation:

Step1: Analyze the mass of ice and water

Bob initially has 900 grams of water and adds 200 grams of ice. When ice melts, it turns into water. The mass of the melted ice (200 grams) is added to the initial mass of water.

Step2: Calculate the total mass of water

The total mass of water in the pitcher is the sum of the initial water mass and the mass of melted ice. So we use the formula \(m = m_{water - initial}+m_{ice - melted}\), where \(m_{water - initial} = 900\space g\) and \(m_{ice - melted}=200\space g\).

$$m=900 + 200$$

$$m = 1100\space g$$

Answer:

1100 g