Question

blue light waves have more energy than red light waves. which of these situations most likely produces a photoelectric effect? you may assume that the same metal is used in each situation. check all that apply.
□ shining dim red light on a strip of metal
□ shining bright red light on a strip of metal
□ shining dim blue light on a strip of metal
□ shining bright blue light on a strip of metal

Explanation:

The photoelectric effect depends on the frequency (energy) of light, not its intensity. Blue light has higher energy (frequency) than red light. So, any blue light (dim or bright) can cause the photoelectric effect if its energy is above the metal's work function, while red light (even bright) has lower energy and is less likely (assuming red light's energy is below the work function here).

• Shining dim red light: Red light has low energy, dim means low intensity. No.
• Shining bright red light: Red light energy is low, brightness (intensity) doesn't add energy per photon. No.
• Shining dim blue light: Blue light has high energy per photon, dim is low intensity but each photon has enough energy. Yes.
• Shining bright blue light: Blue light has high energy per photon, bright means more photons, so definitely enough energy. Yes.

Answer:

• shining dim blue light on a strip of metal
• shining bright blue light on a strip of metal