Question

a ball rolls down a hill. it starts with velocity of ( 2 \frac{m}{s} ). after 2 seconds, the ball has a velocity of ( 12 \frac{m}{s} ). what is the acceleration of the ball? ( 2 \frac{m}{s^{2}} ) ( 4 \frac{m}{s^{2}} ) ( 5 \frac{m}{s^{2}} ) ( 7 \frac{m}{s^{2}} )

Explanation:

Step1: Recall the acceleration formula

The formula for acceleration \(a=\frac{v - u}{t}\), where \(v\) is the final velocity, \(u\) is the initial velocity, and \(t\) is the time.

Step2: Identify the values

Given \(u = 2\frac{m}{s}\), \(v=12\frac{m}{s}\), and \(t = 2s\).

Step3: Substitute the values into the formula

$$
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$$

Answer:

\(5\frac{m}{s^{2}}\) (the third option)