Question

1 your baby grows up and has their own baby! congratulations youre a grandparent! draw a punnett square for the trait of dimples. assume your grandbabys other parent is homozygous for dimples. what is the probability that your grandbaby will have dimples?

Explanation:

Step1: Assume allele for dimples

Let \( D \) represent the dominant allele for dimples and \( d \) represent the recessive allele. If having dimples is a dominant - trait.

Step2: Determine parents' genotypes

Assume your child (grandbaby's parent) has a genotype. Since we are not given information about your child's genotype, but if we assume the most general case (for example, if your child could be \( Dd \) (heterozygous, maybe inherited from you and your partner)). The other parent is homozygous for dimples, so their genotype is \( DD \).

Step3: Create Punnett square

	\( D \)	\( D \)
\( d \)	\( Dd \)	\( Dd \)

Step4: Calculate probability

Out of 4 possible genotypes (\( DD, DD, Dd, Dd \)), all of them (\( 4/4 = 1 \)) result in the phenotype of having dimples (because \( DD \) and \( Dd \) both show the dominant - trait (dimples) if dimples is a dominant trait).

Answer:

The probability that the grandbaby will have dimples is \( 100\%\) (or \( 1\) in fraction form)