Question

1. an average net force of 16.0 n acts on a box for 3.33×10^{-3} min causing it to accelerate from rest to 3.50 m/s. what is the mass of the object?

Explanation:

Step1: Calculate the acceleration

Use the formula \(a=\frac{v - u}{t}\), where \(u = 0\ m/s\) (starts from rest), \(v=3.50\ m/s\), and \(t = 3.33\times10^{-3}\ s\).
\(a=\frac{3.50 - 0}{3.33\times10^{-3}}=\frac{3.50}{3.33\times10^{-3}}\approx1051\ m/s^{2}\)

Step2: Calculate the mass

Use Newton's second law \(F = ma\), so \(m=\frac{F}{a}\). Given \(F = 16.0\ N\) and \(a\approx1051\ m/s^{2}\).
\(m=\frac{16.0}{1051}\approx0.0152\ kg\)

Answer:

The mass of the object is approximately \(0.0152\ kg\)