Question

in the appropriate terms to explore the formation of a peptide bond
drop zones
(chemical structures of amino acids, peptide bond, h₂o, and drop zones for labeling)

Explanation:

To solve this problem about peptide bond formation, we analyze the components and the reaction:

Step 1: Identify the molecules

The top two structures are amino acids. Each amino acid has an amino group ($-\text{NH}_2$), a carboxyl group ($-\text{COOH}$), a hydrogen ($-\text{H}$), and a side chain (labeled "R").

Step 2: Peptide bond formation reaction

When two amino acids form a peptide bond, the carboxyl group of one amino acid reacts with the amino group of another. Specifically:

• The $-\text{OH}$ from the carboxyl group ($-\text{COOH}$) and an $-\text{H}$ from the amino group ($-\text{NH}_2$) are removed as $\text{H}_2\text{O}$ (dehydration synthesis).
• The remaining carbon (from $-\text{COOH}$) and nitrogen (from $-\text{NH}_2$) form a peptide bond ($-\text{CO}-\text{NH}-$).

Labeling the drop zones (from top to bottom, left to right):

1. Top left (first amino acid): Amino acid (contains $-\text{NH}_2$, $-\text{COOH}$, R, H)
2. Top right (second amino acid): Amino acid (contains $-\text{NH}_2$, $-\text{COOH}$, R, H)
3. Middle left (reaction type): Dehydration Synthesis (or Condensation Reaction, since water is removed)
4. Middle right (product before bond): Dipeptide (intermediate, but actually the peptide bond forms to create a dipeptide)
5. Bottom left (side chain of first amino acid): R group (side chain, varies per amino acid)
6. Bottom right (peptide bond product): Dipeptide (after bond formation, with $-\text{CO}-\text{NH}-$ bond)
7. Bottommost left (byproduct): $\text{H}_2\text{O}$ (water, removed during dehydration)

Key Takeaway:

Peptide bond formation occurs via dehydration synthesis (removing $\text{H}_2\text{O}$) between the carboxyl group of one amino acid and the amino group of another, forming a dipeptide.

(Note: If the drop zones require specific labels like "Amino Acid", "Dehydration Synthesis", "Dipeptide", "H₂O", "R Group", etc., assign them based on the reaction steps above.)

Answer:

To solve this problem about peptide bond formation, we analyze the components and the reaction:

Step 1: Identify the molecules

The top two structures are amino acids. Each amino acid has an amino group ($-\text{NH}_2$), a carboxyl group ($-\text{COOH}$), a hydrogen ($-\text{H}$), and a side chain (labeled "R").

Step 2: Peptide bond formation reaction

When two amino acids form a peptide bond, the carboxyl group of one amino acid reacts with the amino group of another. Specifically:

• The $-\text{OH}$ from the carboxyl group ($-\text{COOH}$) and an $-\text{H}$ from the amino group ($-\text{NH}_2$) are removed as $\text{H}_2\text{O}$ (dehydration synthesis).
• The remaining carbon (from $-\text{COOH}$) and nitrogen (from $-\text{NH}_2$) form a peptide bond ($-\text{CO}-\text{NH}-$).

Labeling the drop zones (from top to bottom, left to right):

1. Top left (first amino acid): Amino acid (contains $-\text{NH}_2$, $-\text{COOH}$, R, H)
2. Top right (second amino acid): Amino acid (contains $-\text{NH}_2$, $-\text{COOH}$, R, H)
3. Middle left (reaction type): Dehydration Synthesis (or Condensation Reaction, since water is removed)
4. Middle right (product before bond): Dipeptide (intermediate, but actually the peptide bond forms to create a dipeptide)
5. Bottom left (side chain of first amino acid): R group (side chain, varies per amino acid)
6. Bottom right (peptide bond product): Dipeptide (after bond formation, with $-\text{CO}-\text{NH}-$ bond)
7. Bottommost left (byproduct): $\text{H}_2\text{O}$ (water, removed during dehydration)

Key Takeaway:

Peptide bond formation occurs via dehydration synthesis (removing $\text{H}_2\text{O}$) between the carboxyl group of one amino acid and the amino group of another, forming a dipeptide.

(Note: If the drop zones require specific labels like "Amino Acid", "Dehydration Synthesis", "Dipeptide", "H₂O", "R Group", etc., assign them based on the reaction steps above.)