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4
the voltage remains the same but the resistance becomes twice as large.
what happens to the current intensity?
the current becomes twice as high.
the current is halved.
the current stays the same.
ok
Step1: Recall Ohm's Law
Ohm's Law is \(I=\frac{V}{R}\), where \(I\) is current, \(V\) is voltage, and \(R\) is resistance.
Step2: Substitute new resistance value
Given \(V\) is constant and \(R_{new} = 2R\). Then \(I_{new}=\frac{V}{R_{new}}=\frac{V}{2R}\).
Step3: Compare with original current
Since original \(I=\frac{V}{R}\), so \(I_{new}=\frac{1}{2}I\).
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The current is halved.