Question

an albino woman marries a phenotypically normal man with no family history of albinism (a rare recessive disorder). what percentage of their children are likely to be albino?
50
25
0
100

Explanation:

Step1: Define alleles

Let the normal - allele be \(A\) and the albino - allele be \(a\). The albino woman must have the genotype \(aa\) since albinism is a recessive disorder. The man has no family history of albinism and is phenotypically normal, so his genotype is most likely \(AA\).

Step2: Determine possible genotypes of offspring

When \(aa\) (woman) and \(AA\) (man) have children, all of their children will have the genotype \(Aa\) according to the Punnett - square analysis. \(a\times A\) gives \(Aa\) for all offspring.

Step3: Calculate the percentage of albino children

Since an albino individual has the genotype \(aa\), and none of the children have the \(aa\) genotype (all are \(Aa\)), the percentage of albino children is \(0\).

Answer:

C. 0