Question

the accompanying bar graph shows the resident population and the land area of a particular country for selected years from 1800 through 2019. use the information to find the population density of a certain country, to the nearest tenth, expressed in people per square kilometer, in 1900.
1 in² = 6.5 cm²
1 ft² = 0.09 m²
1 yd² = 0.8 m²
1 mi² = 2.6 km²
1 acre = 0.4 hectare (ha)
click here to view the bar graph.

the population density in 1900 was approximately
(round to the nearest tenth as needed.)

Explanation:

To solve this, we need the population and land area (in square miles, likely) from the bar graph for 1900. Let's assume from typical data (since the graph isn't visible, but common for US or similar):

Step 1: Get Population and Land Area (Assumed Values)

Suppose in 1900, population \( P = 76,212,168 \) people and land area \( A = 3,540,840 \) square miles (common US data).

Step 2: Convert Land Area to Square Kilometers

We know \( 1 \, \text{mi}^2 = 2.6 \, \text{km}^2 \).
So, \( A_{\text{km}^2} = 3,540,840 \times 2.6 \)
\( A_{\text{km}^2} = 9,206,184 \, \text{km}^2 \)

Step 3: Calculate Population Density

Population density \( D = \frac{\text{Population}}{\text{Land Area (km}^2\text{)}} \)
\( D = \frac{76,212,168}{9,206,184} \approx 8.3 \) (rounded to nearest tenth)

(Note: If actual graph values differ, substitute. For example, if population is \( P \) and land area \( A \) (mi²), use \( D = \frac{P}{A \times 2.6} \))

Answer:

\( 8.3 \) (or adjust with actual graph data)