Question

e) \\((-6a)(-4b)(3c) =\\)

Explanation:

Multiplicar los coeficientes numéricos

$$ (-6) \cdot (-4) \cdot 3 = 24 \cdot 3 = 72 $$

Multiplicar las variables algebraicas

$$ a \cdot b \cdot c = abc $$

Combinar los resultados

$$ (-6a)(-4b)(3c) = 72abc $$

Answer:

e) \((-6a)(-4b)(3c) =\) <blank>\(72abc\)</blank>