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573×6 + 4; 573×6; 2,869 + 5 = 573 remainder 4

Question

573×6 + 4; 573×6; 2,869 + 5 = 573 remainder 4

Explanation:

Step1: Calculate \(573\times6\)

\(573\times6 = 3438\)

Step2: Add 4 to the result

\(3438 + 4 = 3442\)

Step3: Calculate \(573\times0\)

\(573\times0 = 0\) (This part seems to be a separate calculation, maybe for comparison or verification, but if we focus on \(573\times6 + 4\), the result is 3442)

Answer:

For \(573\times6 + 4\), the result is 3442; for \(573\times0\), the result is 0. And for the division \(2869\div5\), the quotient is 573 and the remainder is 4 (we can verify it by \(573\times5 + 4=2865 + 4 = 2869\), there might be a typo in the original problem as it wrote \(2,869 + 5\) which should be \(2,869\div5\))