Question

1. two people push a box. one pushes with 30 n to the right, the other with 20 n to the left. what is the net force? 50. a runner increases speed from 2 m/s to 6 m/s in 2 seconds. what is their acceleration?

Explanation:

Step1: Define right - direction as positive

Let the force to the right be positive ($F_1 = 30N$) and the force to the left be negative ($F_2=- 20N$).

Step2: Calculate net force

The net force $F_{net}=F_1 + F_2$. Substitute the values: $F_{net}=30+( - 20)=10N$.

Step3: For acceleration problem

The formula for acceleration is $a=\frac{v_f - v_i}{t}$, where $v_f$ is the final velocity, $v_i$ is the initial velocity and $t$ is the time. Given $v_i = 2m/s$, $v_f=6m/s$ and $t = 2s$.

Step4: Calculate acceleration

$a=\frac{6 - 2}{2}=\frac{4}{2}=2m/s^2$.

Answer:

1. $10N$
2. $2m/s^2$