Question

(3x - 8y = -8) (assumed correction for the first equation)
y = 2 - x
is (0, 1) a solution of the system?
choose 1 answer:
a yes
b no

Explanation:

Step1: Check first equation

Substitute \(x = 0\), \(y = 1\) into \(-3x - 8y=-8\).
Left - hand side (LHS): \(-3(0)-8(1)=0 - 8=-8\).
Right - hand side (RHS): \(-8\).
Since \(LHS = RHS\) for the first equation.

Step2: Check second equation

Substitute \(x = 0\), \(y = 1\) into \(y = 2 - x\).
Left - hand side (LHS): \(y = 1\).
Right - hand side (RHS): \(2-0 = 2\).
Since \(1
eq2\), \(LHS
eq RHS\) for the second equation. A solution of the system must satisfy both equations.

Answer:

B. No