Question

1. calculate the sum of 6.078 g and 0.3329 g.
2. subtract 7.11 cm from 8.2 cm. (hint: see sample problem e.)
3. what is the product of 0.8102 m and 3.44 m?
4. divide 94.20 g by 3.16722 ml.
5. write the following numbers in scientific notation.

a. 0.0006730
b. 50000.0
c. 0.000003010

1. the following numbers are in scientific notation. write them in standard notation.

a. 7.050×10³ g
b. 4.00005×10⁷ mg
c. 2.3500×10⁴ ml

1. perform the following operation. express the answer in scientific notation and with the correct number of significant figures. 0.002115 m×0.0000405 m
2. a sample of a certain material has a mass of 2.03×10⁻³ g. calculate the volume of the sample, given that the density is 9.133×10⁻¹ g/cm³. use the four - step method to solve the problem. (hint: see sample problem f.)

Explanation:

39.

Step1: Add the two masses

$6.078 + 0.3329=6.4109$ g

Step1: Subtract the lengths

$8.2 - 7.11 = 1.09$ cm

Step1: Multiply the two lengths

$0.8102\times3.44 = 2.787088$ m²

Answer:

$6.4109$ g

40.