Question

if (-3, -38) and (8, 61) are two anchor points on a trend line, then find the equation of the line. y = ?x +

Explanation:

Step1: Calculate the slope

The slope $m$ of a line passing through two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by $m=\frac{y_2 - y_1}{x_2 - x_1}$. Here, $x_1=-3,y_1 = - 38,x_2=8,y_2 = 61$. So $m=\frac{61-(-38)}{8-(-3)}=\frac{61 + 38}{8 + 3}=\frac{99}{11}=9$.

Step2: Find the y - intercept

Use the point - slope form $y - y_1=m(x - x_1)$ and then convert it to slope - intercept form $y=mx + b$. Let's use the point $(-3,-38)$ and $m = 9$. Substitute into $y - y_1=m(x - x_1)$: $y-(-38)=9(x-(-3))$, which simplifies to $y + 38=9(x + 3)$. Expand the right side: $y+38=9x+27$. Then solve for $y$: $y=9x+27 - 38=9x - 11$.

Answer:

$y = 9x-11$