Question

\\((n^0 \cdot 2n)^{-3}\\)

Explanation:

Simplify the expression inside the parentheses

$$ n^0 \cdot 2n = 1 \cdot 2n = 2n $$

Apply the negative exponent rule

$$ (2n)^{-3} = \frac{1}{(2n)^3} $$

Distribute the exponent to the terms inside the parentheses

$$ \frac{1}{(2n)^3} = \frac{1}{2^3 \cdot n^3} = \frac{1}{8n^3} $$

Answer:

$$\frac{1}{8n^3}$$