Question

26 solve algebraically for x: 3(x + 1) - 5x = 12 - (6x - 7)

Explanation:

Step1: Expand both sides

Expand $3(x + 1)-5x$ to get $3x+3 - 5x$, and expand $12-(6x - 7)$ to get $12-6x + 7$.
So the equation becomes $3x+3 - 5x=12-6x + 7$.

Step2: Combine like - terms on both sides

On the left - hand side, $3x-5x=-2x$, so it's $-2x + 3$. On the right - hand side, $12 + 7 = 19$, so it's $19-6x$.
The equation is now $-2x+3=19-6x$.

Step3: Add $6x$ to both sides

$-2x+6x + 3=19-6x+6x$.
$4x+3=19$.

Step4: Subtract 3 from both sides

$4x+3 - 3=19 - 3$.
$4x=16$.

Step5: Divide both sides by 4

$\frac{4x}{4}=\frac{16}{4}$.
$x = 4$.

Answer:

$x = 4$