trazar la recta. $y=\\frac{3}{5}x - 1$
To graph \(y = \frac{3}{5}x-1\), plot \((0, - 1)\) (y - intercept) and \((5,2)\) (using slope \(\frac{3}{5}\)), then draw a line through these points.
To graph \(y = \frac{3}{5}x-1\), plot \((0, - 1)\) (y - intercept) and \((5,2)\) (using slope \(\frac{3}{5}\)), then draw a line through these points.
trazar la recta.
$y=\\frac{3}{5}x - 1$
trazar la recta.
$y=\\frac{3}{5}x - 1$
The equation is in slope - intercept form \(y = mx + b\), where \(b\) is the y - intercept. For \(y=\frac{3}{5}x - 1\), \(b=- 1\). So the line crosses the y - axis at the point \((0,-1)\).
The slope \(m=\frac{3}{5}\), which means for a run of 5 (change in \(x\)), the rise is 3 (change in \(y\)). Starting from \((0,-1)\), if we move 5 units to the right (increase \(x\) by 5, so \(x = 0+5 = 5\)) and 3 units up (increase \(y\) by 3, so \(y=-1 + 3=2\)), we get the point \((5,2)\).
Plot the points \((0,-1)\) and \((5,2)\) on the coordinate plane. Then, use a straight - edge to draw a line passing through these two points. This line represents the equation \(y=\frac{3}{5}x - 1\).
(Note: Since the problem is about graphing, the main steps are identifying key points using the slope - intercept form and then plotting and drawing the line. If you were to describe the graph, the line has a positive slope, crosses the y - axis at \((0,-1)\) and passes through \((5,2)\) among other points.)
To graph \(y = \frac{3}{5}x-1\), plot \((0, - 1)\) (y - intercept) and \((5,2)\) (using slope \(\frac{3}{5}\)), then draw a line through these points.
The equation is in slope - intercept form \(y = mx + b\), where \(b\) is the y - intercept. For \(y=\frac{3}{5}x - 1\), \(b=- 1\). So the line crosses the y - axis at the point \((0,-1)\).
The slope \(m=\frac{3}{5}\), which means for a run of 5 (change in \(x\)), the rise is 3 (change in \(y\)). Starting from \((0,-1)\), if we move 5 units to the right (increase \(x\) by 5, so \(x = 0+5 = 5\)) and 3 units up (increase \(y\) by 3, so \(y=-1 + 3=2\)), we get the point \((5,2)\).
Plot the points \((0,-1)\) and \((5,2)\) on the coordinate plane. Then, use a straight - edge to draw a line passing through these two points. This line represents the equation \(y=\frac{3}{5}x - 1\).
(Note: Since the problem is about graphing, the main steps are identifying key points using the slope - intercept form and then plotting and drawing the line. If you were to describe the graph, the line has a positive slope, crosses the y - axis at \((0,-1)\) and passes through \((5,2)\) among other points.)
To graph \(y = \frac{3}{5}x-1\), plot \((0, - 1)\) (y - intercept) and \((5,2)\) (using slope \(\frac{3}{5}\)), then draw a line through these points.
trazar la recta.
$y=\\frac{3}{5}x - 1$
Top-left cell: 180 Top-right cell: 6 Bottom-left cell: 600 Bottom-right cell: 20 Final product: 806
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