- First blank: y-axis
- Second blank: x-values
- Third blank: y-values
Filled sentence:
Horizontal transformations reflect a function over the y-axis. Thus, they transform a given function $y = f(x)$ to $y = f(-x)$. To reflect a given function horizontally, multiply all x-values by $-1$ while keeping the y-values the same.
Turn 2 Answer
Got it! First, let's remember that the horizontal reflection of \( f(x) = x^3 \) is \( g(x) = f(-x) = (-x)^3 = -x^3 \).
Let me make a sample table with common x-values to show both the original and reflected function values:
| x | Original \( f(x) = x^3 \) | Reflected \( g(x) = -x^3 \) |
|----|---------------------------|------------------------------|
| -2 | \( (-2)^3 = -8 \) | \( -(-2)^3 = 8 \) |
| -1 | \( (-1)^3 = -1 \) | \( -(-1)^3 = 1 \) |
| 0 | \( 0^3 = 0 \) | \( -0^3 = 0 \) |
| 1 | \( 1^3 = 1 \) | \( -1^3 = -1 \) |
| 2 | \( 2^3 = 8 \) | \( -2^3 = -8 \) |
See how each reflected y-value is just the opposite of the original? That’s the horizontal flip over the y-axis doing its thing. Did you have specific x-values you needed to fill in, or is this enough? 😊
Turn 3 Answer
Got you, let's fill those in quick!
Since the original function is \( f(x) = x^3 \), the horizontal reflection is \( f(-x) = (-x)^3 \). Let's calculate each one:
- When x = 0: \( f(-0) = (-0)^3 = 0 \)
- When x = 1: \( f(-1) = (-1)^3 = -1 \)
- When x = 2: \( f(-2) = (-2)^3 = -8 \)
So the blanks under f(-x) are 0, -1, -8 in order! 😎
Turn 4 Answer
Got it, let's work through this step by step!
First, remember that f(-x) means we take each given x-value, flip its sign, then find the corresponding y-value from the parabola's points you described.
Let's go one by one:
- When x = -1: We calculate -x = -(-1) = 1. Looking at your parabola, when x=1, the y-value is -2. So f(-1) = -2
- When x = -2: -x = -(-2) = 2. The vertex is at (2, 0), so the y-value here is 0. So f(-2) = 0
- When x = -3: -x = -(-3) = 3. Your parabola passes through (3, -2), so the y-value is -2. So f(-3) = -2
To recap, the blanks (in order for x=-1, -2, -3) are: -2, 0, -2
Turn 5 Answer
Got it, let's break this down simply!
First, the horizontal reflection of \( F(x) = (x+1)^2 \) is \( F(-x) = (-x + 1)^2 \).
Now, to find where the point (-4, 9) maps to on the reflected function:
When we do a horizontal reflection, we flip the sign of the original x-value (because we're replacing x with -x in the function). The y-value stays the same, since horizontal transformations don't affect the output.
Original x-coordinate: -4 → flipped x-coordinate is -(-4) = 4
Original y-coordinate: 9 → stays 9
Wait, let's double-check by plugging in to confirm: \( F(-4) = (-4 + 1)^2 = (-3)^2 = 9 \) (that's the original point). For the reflected function, plug x=4: \( F(-4) \) is the original, but the reflected function at x=4 is \( F(-(4)) = F(-4) = 9 \). Yep, that matches.
So (-4, 9) reflects to (4, 9) in \( f(-x) \)!
Turn 6 Answer
Got it, let's figure this out! A horizontal reflection (which is what f(-x) is) flips the x-coordinate's sign but keeps the y-coordinate the same.
Since (3, -5) is on f(x), we just flip the x-value from 3 to -3, and leave y as -5. So the point on f(-x) is (-3, -5)! 😊