Question

1. in rabbits, short fur (s) is dominant over long fur (s). a homozygous dominant rabbit is crossed with a heterozygous rabbit. what is the probability that an offspring will be heterozygous for fur length.

Explanation:

Step1: Determine the genotypes of the parents

A homozygous dominant rabbit has the genotype \(SS\). A heterozygous rabbit has the genotype \(Ss\).

Step2: Set up the Punnett square

The possible gametes from the \(SS\) parent are all \(S\). The possible gametes from the \(Ss\) parent are \(S\) and \(s\).

	\(S\)	\(s\)
\(S\)	\(SS\)	\(Ss\)

Step3: Calculate the probability of heterozygous offspring

Out of the 4 possible offspring genotypes (\(SS, Ss, SS, Ss\)), 2 are \(Ss\) (heterozygous). So the probability is \(\frac{2}{4}=\frac{1}{2}\)

Answer:

The probability that an offspring will be heterozygous for fur length is \(\frac{1}{2}\)