Question

20.) if a neutron star emits beams of radiation as it rotates at 1000 times per second, what is the period of the pulsar?

Explanation:

Step1: Recall the relationship between frequency and period

The frequency \(f\) and period \(T\) are related by the formula \(T=\frac{1}{f}\).

Step2: Identify the frequency

The neutron star rotates 1000 times per second. So the frequency \(f = 1000\space Hz\) (since frequency is the number of rotations per second).

Step3: Calculate the period

Substitute \(f = 1000\space Hz\) into the formula \(T=\frac{1}{f}\). Then \(T=\frac{1}{1000}\space s= 0.001\space s\)

Answer:

The period of the pulsar is \(0.001\space s\)