Question

14 multiple choice 1 point a dominant mutation in humans is designated d. if a heterozygous male with this mutation is married to a normal female, whats the chance for the couple to have a baby with this mutation? one quarter one half three quarters 100%

Explanation:

Step1: Determine Genotypes

The heterozygous male has genotype \( Dd \) (since dominant mutation is \( D \), heterozygous means one dominant and one recessive allele). The normal female, as the mutation is dominant, must have genotype \( dd \) (recessive alleles only, so no mutation expressed).

Step2: Set Up Punnett Square

	\( D \)	\( d \)
\( d \)	\( Dd \)	\( dd \)

Step3: Analyze Offspring Genotypes

From the Punnett square, the possible offspring genotypes are \( Dd \) (with mutation, since \( D \) is dominant) and \( dd \) (without mutation). There are 2 \( Dd \) and 2 \( dd \) out of 4 total, so the probability of having a baby with the mutation (\( Dd \)) is \( \frac{2}{4}=\frac{1}{2} \).

Answer:

One half (the option corresponding to "One half")