Question

1. $(-6) + 7 + (-5)$
2. $8 + 3 + (-4)$
3. $3 - 7 - (-4)$
4. $(-7) + 8 - (-1)$

evaluate each expression.

1. $1 - 1 + (-5) - (-5)$
2. $2 + (-3) + 2 - 4$
3. $4 + 1 + 1 - 3$
4. $(-5) + 5 + (-1) + (-4)$

find each quotient.

1. $-30 \div 6$
2. $0 \div 7$

Explanation:

Problem 13: $(-6) + 7 + (-5)$

Step 1: Add the first two numbers

$(-6) + 7 = 1$

Step 2: Add the result to the third number

$1 + (-5) = -4$

Step 1: Add the first two numbers

$8 + 3 = 11$

Step 2: Add the result to the third number

$11 + (-4) = 7$

Step 1: Subtract the second number from the first

$3 - 7 = -4$

Step 2: Subtract the negative number (which is equivalent to adding)

$-4 - (-4) = -4 + 4 = 0$

Answer:

$-4$

Problem 14: $8 + 3 + (-4)$