Question

1. a 120 g ball is placed in a catapult. when the catapult releases, it applies a pressure of 1598 n, what is the acceleration of the ball as it moves through the air?

Explanation:

Step1: Convert mass to kg

Given mass \(m = 120g=0.12kg\) (since \(1kg = 1000g\)).

Step2: Use Newton's second law \(F = ma\)

We know \(F = 1598N\) and \(m = 0.12kg\). Rearranging for \(a\), we get \(a=\frac{F}{m}\).
Substitute \(F = 1598N\) and \(m = 0.12kg\) into the formula: \(a=\frac{1598}{0.12}\).
Calculate \(\frac{1598}{0.12}\approx13316.67m/s^{2}\).

Answer:

The acceleration of the ball is approximately \(13316.67m/s^{2}\).