Question

12 a gas has a pressure of 450 kpa at 350 k. at what temperature will the pressure rise to 600 kpa?

Explanation:

Step1: Apply Gay - Lussac's Law

Gay - Lussac's Law is \( \frac{P_1}{T_1}=\frac{P_2}{T_2} \), where \( P_1 = 450\ \text{kPa}\), \( T_1=350\ \text{K}\), \( P_2 = 600\ \text{kPa}\), and \( T_2\) is the unknown temperature.

Step2: Solve for \( T_2 \)

Rearrange the formula to \( T_2=\frac{P_2\times T_1}{P_1} \). Substitute the values: \( T_2=\frac{600\times350}{450}\).
Calculate \( 600\times350 = 210000\), then \( \frac{210000}{450}=\frac{1400}{3}\approx466.67\ \text{K}\).

Answer:

\( 466.67\ \text{K}\)