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12,8 = 2,4(2n - 6) 27,2 ÷ 0,8 4(34)+ 6=34 248 f) y + (y+0,5) + (3y + 1,…

Question

12,8 = 2,4(2n - 6)
27,2 ÷ 0,8
4(34)+
6=34
248
f) y + (y+0,5) + (3y + 1,75) = 6
=34

Explanation:

Step1: Combine like terms

First, we expand the left - hand side of the equation \(y+(y + 0.5)+(3y+1.75)=6\).
When we remove the parentheses, we get \(y + y+0.5 + 3y+1.75 = 6\).
Then we combine the \(y\) - terms: \(y + y+3y=(1 + 1+3)y = 5y\), and combine the constant terms: \(0.5 + 1.75=2.25\).
So the equation becomes \(5y+2.25 = 6\).

Step2: Isolate the variable term

Subtract \(2.25\) from both sides of the equation \(5y+2.25 = 6\).
Using the subtraction property of equality (\(a=b\Rightarrow a - c=b - c\)), we have \(5y+2.25-2.25=6 - 2.25\).
Simplifying both sides, we get \(5y=3.75\).

Step3: Solve for y

Divide both sides of the equation \(5y = 3.75\) by \(5\).
Using the division property of equality (\(a=b\Rightarrow\frac{a}{c}=\frac{b}{c},c
eq0\)), we have \(y=\frac{3.75}{5}\).
Calculating \(\frac{3.75}{5}=0.75\).

Answer:

\(y = 0.75\)