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12) $-7(6b - 8) = 392$ 14) $-7(7 - 6x) = -91$ 16) $-7(2p + 4) + 5 = -13…

Question

  1. $-7(6b - 8) = 392$
  2. $-7(7 - 6x) = -91$
  3. $-7(2p + 4) + 5 = -135$
  4. $-5(-5m + 7) + 6 = 146$
  5. $9 = n - 7 + 3n$
  6. you had $24 to spend on four avo

after buying them you had $16.
much did each avocado cost?

Explanation:

Problem 12: $-7(6b - 8) = 392$

Step 1: Divide both sides by -7

$\frac{-7(6b - 8)}{-7} = \frac{392}{-7}$
$6b - 8 = -56$

Step 2: Add 8 to both sides

$6b - 8 + 8 = -56 + 8$
$6b = -48$

Step 3: Divide both sides by 6

$\frac{6b}{6} = \frac{-48}{6}$
$b = -8$

Step 1: Divide both sides by -7

$\frac{-7(7 - 6x)}{-7} = \frac{-91}{-7}$
$7 - 6x = 13$

Step 2: Subtract 7 from both sides

$7 - 6x - 7 = 13 - 7$
$-6x = 6$

Step 3: Divide both sides by -6

$\frac{-6x}{-6} = \frac{6}{-6}$
$x = -1$

Step 1: Subtract 5 from both sides

$-7(2p + 4) + 5 - 5 = -135 - 5$
$-7(2p + 4) = -140$

Step 2: Divide both sides by -7

$\frac{-7(2p + 4)}{-7} = \frac{-140}{-7}$
$2p + 4 = 20$

Step 3: Subtract 4 from both sides

$2p + 4 - 4 = 20 - 4$
$2p = 16$

Step 4: Divide both sides by 2

$\frac{2p}{2} = \frac{16}{2}$
$p = 8$

Answer:

$b = -8$

Problem 14: $-7(7 - 6x) = -91$