7. if you walked 20 meters, took a book from the table and then walked back to your seat in a total of 1 minute,
a. what was you speed?
b. what was your velocity?

8. fred the snail crawled east to frank’s house to get a snack for evie’s birthday party. frank’s house was 1 meter to the east. he took 10 minutes to get there. fred then turned around, and crawled west, past his own house to evies’s house. evie’s house was 1 meter past his own house, so he crawled 2 meters west from frank’s house to get there, and took another 10 minutes. (complete the following questions. show your work.)
a. what was fred’s total speed, from the time he left his house till he arrived at the party?
b. what was the distance he travelled?
c. what was his displacement?
d. what was his velocity west?

Question

7. if you walked 20 meters, took a book from the table and then walked back to your seat in a total of 1 minute,
   a. what was you speed?
   b. what was your velocity?

8. fred the snail crawled east to frank’s house to get a snack for evie’s birthday party. frank’s house was 1 meter to the east. he took 10 minutes to get there. fred then turned around, and crawled west, past his own house to evies’s house. evie’s house was 1 meter past his own house, so he crawled 2 meters west from frank’s house to get there, and took another 10 minutes. (complete the following questions. show your work.)
   a. what was fred’s total speed, from the time he left his house till he arrived at the party?
   b. what was the distance he travelled?
   c. what was his displacement?
   d. what was his velocity west?

Accepted Answer

### Question 7
#### Part a: Speed Calculation
# Explanation:
## Step1: Determine total distance
You walked 20 m to the table and 20 m back, so total distance $d = 20 + 20 = 40$ meters.
## Step2: Convert time to seconds
Total time $t = 1$ minute $= 60$ seconds.
## Step3: Calculate speed
Speed formula: $v_{speed} = \frac{d}{t}$. Substitute $d = 40$ m, $t = 60$ s: $v_{speed} = \frac{40}{60} = \frac{2}{3} \approx 0.67$ m/s.
# Answer: $\frac{2}{3}$ m/s (or approximately 0.67 m/s)

#### Part b: Velocity Calculation
# Explanation:
## Step1: Determine displacement
Displacement is final position - initial position. You started at your seat, went 20 m, then came back 20 m, so displacement $s = 0$ meters.
## Step2: Calculate velocity
Velocity formula: $v_{velocity} = \frac{s}{t}$. Substitute $s = 0$ m, $t = 60$ s: $v_{velocity} = \frac{0}{60} = 0$ m/s.
# Answer: 0 m/s

### Question 8
#### Part a: Total Speed of Fred
# Explanation:
## Step1: Determine total distance
Fred crawled 1 m east to Frank’s house, then 2 m west to Evie’s house. Total distance $d = 1 + 2 = 3$ meters.
## Step2: Determine total time
Total time $t = 10 + 10 = 20$ minutes $= 20 	imes 60 = 1200$ seconds (or keep in minutes for speed in m/min: $t = 20$ min).
## Step3: Calculate speed (using minutes for simplicity)
Speed formula: $v_{speed} = \frac{d}{t}$. Substitute $d = 3$ m, $t = 20$ min: $v_{speed} = \frac{3}{20} = 0.15$ m/min. (Or in m/s: $\frac{3}{1200} = 0.0025$ m/s)
# Answer: 0.15 m/min (or 0.0025 m/s)

#### Part b: Distance Travelled
# Explanation:
## Step1: Sum individual distances
Distance east: 1 m, distance west: 2 m. Total distance $d = 1 + 2 = 3$ meters.
# Answer: 3 meters

#### Part c: Displacement of Fred
# Explanation:
## Step1: Define reference point (Fred’s house: position 0)
- East to Frank’s house: position becomes $+1$ m (east is positive).
- West to Evie’s house: moves 2 m west from Frank’s house (position +1 m), so final position: $1 - 2 = -1$ m? Wait, no: Evie’s house is 1 m past his own house (west of his house). So from Fred’s house (0), Frank’s is +1 m east. Then west 2 m: from +1, subtract 2: $1 - 2 = -1$? Wait, no—“1 meter past his own house” west: so displacement is final position - initial position. Initial position: 0 (Fred’s house). Final position: -1 m? Wait, no: “Evie’s house was 1 meter past his own house, so he crawled 2 meters west from Frank’s house to get there.” So Frank’s house is 1 m east of Fred’s (position +1). Then west 2 m: first 1 m west to Fred’s house (position 0), then 1 m west to Evie’s (position -1). So displacement $s = -1 - 0 = -1$ m? Wait, no—displacement is final position - initial position. Initial: 0. Final: -1 m (1 m west of Fred’s house). Wait, but let's re-express:

- East: 1 m (displacement +1 m from start).
- West: 2 m (so from +1, move -2 m: final position $1 - 2 = -1$ m).
- Displacement: $-1 - 0 = -1$ m (or 1 m west).
# Answer: 1 meter west (or -1 m, if east is positive)

#### Part d: Velocity West
# Explanation:
## Step1: Distance west and time west
Distance west: 2 m. Time west: 10 minutes $= 600$ seconds (or 10 min).
## Step2: Calculate velocity (west is positive here, or use direction)
Velocity formula: $v = \frac{d}{t}$. For westward motion, distance is 2 m, time is 10 min $= 600$ s. So $v = \frac{2}{600} = \frac{1}{300} \approx 0.0033$ m/s (or in m/min: $\frac{2}{10} = 0.2$ m/min).
# Answer: 0.2 m/min (or $\frac{1}{300}$ m/s, approximately 0.0033 m/s)

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QUESTION IMAGE

Question

Explanation:

Question 7

Part a: Speed Calculation

Step1: Determine total distance

Step2: Convert time to seconds

Step3: Calculate speed

Step1: Determine displacement

Step2: Calculate velocity

Step1: Determine total distance

Step2: Determine total time

Step3: Calculate speed (using minutes for simplicity)

Answer:

Part b: Velocity Calculation