Question

you have a mixture of 5.9 g of n₂ and 6.2 g of o₂. what is the mole fraction of n₂? report your answer to 2 places after the decimal point.

Explanation:

Step1: Calculate moles of \( \text{N}_2 \)

Molar mass of \( \text{N}_2 \) is \( 2 \times 14.01 = 28.02 \, \text{g/mol} \).
Moles of \( \text{N}_2 = \frac{5.9 \, \text{g}}{28.02 \, \text{g/mol}} \approx 0.2106 \, \text{mol} \).

Step2: Calculate moles of \( \text{O}_2 \)

Molar mass of \( \text{O}_2 \) is \( 2 \times 16.00 = 32.00 \, \text{g/mol} \).
Moles of \( \text{O}_2 = \frac{6.2 \, \text{g}}{32.00 \, \text{g/mol}} \approx 0.1938 \, \text{mol} \).

Step3: Calculate total moles

Total moles \( = 0.2106 + 0.1938 = 0.4044 \, \text{mol} \).

Step4: Calculate mole fraction of \( \text{N}_2 \)

Mole fraction of \( \text{N}_2 = \frac{\text{Moles of } \text{N}_2}{\text{Total moles}} = \frac{0.2106}{0.4044} \approx 0.52 \).

Answer:

\( 0.52 \)