QUESTION IMAGE
Question
(you) \\( m \\) is the midpoint of \\( \overline{pq} \\), and \\( \overline{lm} \\) is the perpendicular bisector of \\( \overline{pq} \\). write a two - column proof to show that \\( lp = lq \\).
statements
- \\( pm = qm \\), \\( lm \perp pq \\)
- \\( lm = lm \\)
3.
- \\( \triangle pml \cong \triangle qml \\)
5.
- \\( lp = lq
reasons
- given
2.
- right angle congruence theorem
4.
- corresponding parts of congruent triangles are congruent.
6.
(left side list of statements/reasons for selection: \\( lm = lm \\), \\( lm \perp pq \\), \\( \angle lmp = \angle lmq \\), \\( lp = lq \\), \\( \angle lmp \cong \angle lmq \\), \\( \triangle pml \cong \triangle qml \\), reflexive property of congruence, sas congruence theorem, hl congruence theorem, sss congruence theorem, definition of segment congruence)
Step1: Analyze Given Information
We know \( \overline{PM} \cong \overline{QM} \) (given as \( PM = QM \) in statement 1), and \( \overline{LM} \) is the perpendicular bisector of \( \overline{PQ} \), so \( \angle PLM \) and \( \angle QLM \) are right angles (by definition of perpendicular bisector), and \( \overline{LM} \cong \overline{LM} \) (reflexive property).
Step2: Identify Triangle Congruence
For \( \triangle PLM \) and \( \triangle QLM \), we have:
- \( \overline{PM} \cong \overline{QM} \) (given)
- \( \overline{LM} \cong \overline{LM} \) (reflexive)
- \( \angle PLM \cong \angle QLM = 90^\circ \) (perpendicular bisector)
By the Hypotenuse - Leg (HL) Congruence Theorem (since they are right triangles, hypotenuse \( PM = QM \) and leg \( LM = LM \)), \( \triangle PLM \cong \triangle QLM \).
Step3: Corresponding Parts of Congruent Triangles
Since \( \triangle PLM \cong \triangle QLM \), their corresponding parts \( \overline{LP} \) and \( \overline{LQ} \) are congruent (CPCTC: Corresponding Parts of Congruent Triangles are Congruent). So \( LP = LQ \).
Now, let's fill the two - column proof:
Statements Column:
- \( PM = QM \), \( \overline{LM} \perp \overline{PQ} \) (Given)
- \( \angle PLM \) and \( \angle QLM \) are right angles (Definition of perpendicular bisector)
- \( LM = LM \) (Reflexive Property of Congruence)
- \( \triangle PLM \cong \triangle QLM \) (HL Congruence Theorem)
- \( LP = LQ \) (CPCTC)
Reasons Column:
- Given
- Definition of perpendicular bisector (A line perpendicular to a segment forms right angles with the segment)
- Reflexive Property of Congruence (A segment is congruent to itself)
- HL Congruence Theorem (If the hypotenuse and a leg of one right triangle are congruent to the hypotenuse and a leg of another right triangle, the triangles are congruent)
- Corresponding Parts of Congruent Triangles are Congruent (CPCTC)
Snap & solve any problem in the app
Get step-by-step solutions on Sovi AI
Photo-based solutions with guided steps
Explore more problems and detailed explanations
The two - column proof is filled as follows:
| Statements | Reasons |
|---|---|
| 2. \( \angle PLM \) and \( \angle QLM \) are right angles | 2. Definition of perpendicular bisector |
| 3. \( LM = LM \) | 3. Reflexive Property of Congruence |
| 4. \( \triangle PLM \cong \triangle QLM \) | 4. HL Congruence Theorem |
| 5. \( LP = LQ \) | 5. CPCTC |