Question

1. if you were to cut an aluminum bar in half the density of each half would be

a. less than the original sample
b. the same as the original sample
c. greater than the original sample

1. in which phase state do most earth materials have their greatest density?

a. gaseous
b. liquid
c. solid

1. if a material is heated and expands, the density of the material will

a. decrease
b. increase
c. remain the same

1. the volume of an irregular object could best be determined by

a. placing it in a beaker of water
b. calculating the circumference
c. comparing it to a known standard for mass
d. counting the number of flat surfaces

1. what is the density of a rock which has a mass of 35 grams and a volume of 7 cm³?

a. 42.0 g/cm³
b. 0.2 g/cm³
c. 28.0 g/cm³
d. 5.0 g/cm³

1. what is the approximate volume of a cube where all sides are equal to 2.5 cm?

a. 2.5 cm³
b. 6.3 cm³
c. 15.6 cm³
d. 39.1 cm³

1. what is the density of a mineral which has a mass of 100 grams and a volume of 25 cm³?

a. 0.25 g/cm³
b. 2.5 g/cm³
c. 4.0 g/cm³
d. 2,500 g/cm³

1. what is the density of a piece of lead that has a mass of 253.1 grams and a volume of 22.4 cm³?

a. 3.4 g/cm³
b. 9.5 g/cm³
c. 11.3 g/cm³
d. 15.8 g/cm³

Explanation:

Step1: Calcular la densidad para la pregunta 5

La fórmula de la densidad es \(
ho=\frac{m}{V} \), donde \( m = 35\ g \) y \( V=7\ cm^{3} \). Entonces \(
ho=\frac{35}{7} \)

Step2: Simplificar la expresión

\( \frac{35}{7}=5\ g/cm^{3} \)

Step3: Calcular el volumen para la pregunta 6

El volumen de un cubo es \( V = s^{3} \), donde \( s = 2.5\ cm \). Entonces \( V=(2.5)^{3}=2.5\times2.5\times2.5 \)

Step4: Realizar la multiplicación

\( 2.5\times2.5 = 6.25 \), luego \( 6.25\times2.5=15.625\approx15.6\ cm^{3} \)

Step5: Calcular la densidad para la pregunta 7

Usando la fórmula \(
ho=\frac{m}{V} \), con \( m = 100\ g \) y \( V = 25\ cm^{3} \). Entonces \(
ho=\frac{100}{25} \)

Step6: Simplificar

\( \frac{100}{25}=4\ g/cm^{3} \)

Step7: Calcular la densidad para la pregunta 8

Con \(
ho=\frac{m}{V} \), \( m = 253.1\ g \) y \( V=22.4\ cm^{3} \). Entonces \(
ho=\frac{253.1}{22.4} \)

Step8: Realizar la división

\( \frac{253.1}{22.4}\approx11.3\ g/cm^{3} \)

Answer:

1. B. the same as the original sample
2. C. solid
3. A. decrease
4. A. placing it in a beaker of water
5. D. \( 5.0\ g/cm^{3} \)
6. C. \( 15.6\ cm^{3} \)
7. C. \( 4.0\ g/cm^{3} \)
8. C. \( 11.3\ g/cm^{3} \)