Question

if you have 910 ml of a 0.638 m hcl solution and you want to dilute it to exactly 0.100 m, how much water, in l, should you add? report your answer to the first place after the decimal point.

Explanation:

Step1: Use the dilution formula

The dilution formula is \(C_1V_1 = C_2V_2\), where \(C_1 = 0.638\space M\), \(V_1=910\space mL = 0.910\space L\), and \(C_2 = 0.100\space M\).
Substitute the values into the formula: \(0.638\times0.910=0.100\times V_2\).

Step2: Solve for \(V_2\)

$$
LATEXBLOCK0
$$

Step3: Calculate the volume of water to add

The volume of water to add, \(V_{water}=V_2 - V_1\).
\(V_{water}=5.8058 - 0.910=4.8958\space L\approx4.9\space L\)

Answer:

\(4.9\)