Question

ws 1: ionic bonding
for each pair of elements below, draw lewis dot structures to show the transfer of electrons. then draw the resulting compound. complete the table below for each reaction.
reactions

1. li + cl

reactions

1. ca + o

reactions

1. be + f

reactions

1. al + cl

reactions

1. al + o

Explanation:

Step1: Analyze Li + Cl

Li (Lithium) has 1 valence electron and is a metal. Cl (Chlorine) has 7 valence electrons and is a non - metal. Li loses 1 electron to achieve a stable electron configuration, and Cl gains 1 electron. The ions formed are Li⁺ and Cl⁻.

Step2: Analyze Ca + O

Ca (Calcium) has 2 valence electrons and is a metal. O (Oxygen) has 6 valence electrons and is a non - metal. Ca loses 2 electrons and O gains 2 electrons. The ions formed are Ca²⁺ and O²⁻.

Step3: Analyze Be + F

Be (Beryllium) has 2 valence electrons and is a metal. F (Fluorine) has 7 valence electrons and is a non - metal. Be loses 2 electrons and each F atom gains 1 electron. The ions formed are Be²⁺ and F⁻.

Step4: Analyze Al + Cl

Al (Aluminum) has 3 valence electrons and is a metal. Cl has 7 valence electrons and is a non - metal. Al loses 3 electrons and each Cl gains 1 electron. The ions formed are Al³⁺ and Cl⁻.

Step5: Analyze Al + O

Al has 3 valence electrons and is a metal. O has 6 valence electrons and is a non - metal. Al loses 3 electrons and O gains 2 electrons. To balance the charges, 2 Al atoms will lose a total of 6 electrons and 3 O atoms will gain a total of 6 electrons. The ions formed are Al³⁺ and O²⁻.

Answer:

Reactions	Atoms	Valence Electrons	Loses/Gains how many	Ions formed
2) Ca + O	Ca, O	2, 6	Ca loses 2, O gains 2	Ca²⁺, O²⁻
3) Be + F	Be, F	2, 7	Be loses 2, F gains 1	Be²⁺, F⁻
4) Al + Cl	Al, Cl	3, 7	Al loses 3, Cl gains 1	Al³⁺, Cl⁻
5) Al + O	Al, O	3, 6	Al loses 3, O gains 2	Al³⁺, O²⁻