Question

write the name for sn(so4)2. remember that sn forms several ions.
o tin sulfide
o tin (i) sulfate
o tin (ii) sulfite
o tin (iv) sulfate
o tin (i) sulfite

question 18
1 pts
write the formula for calcium phosphate.
o ca(po4)
o ca3(po4)3
o ca2(po4)3
o ca2(po4)2
o ca3(po4)2

Explanation:

Step1: Analyze Sn(SO₄)₂

The sulfate ion (SO₄²⁻) has a - 2 charge. There are 2 sulfate ions, so the total negative charge is - 4. For the compound to be neutral, the tin (Sn) ion must have a + 4 charge. The name of Sn(SO₄)₂ is tin(IV) sulfate.

Step2: Analyze calcium phosphate

Calcium (Ca) has a + 2 charge (Ca²⁺) and the phosphate ion (PO₄³⁻) has a - 3 charge. To balance the charges, we need 3 calcium ions (total + 6 charge) and 2 phosphate ions (total - 6 charge). The formula for calcium phosphate is Ca₃(PO₄)₂.

Answer:

tin (IV) sulfate
Ca₃(PO₄)₂