Question

1. write the long - form electron configuration of the following elements?

i. lithium
ii. magnesium
iii. potassium
iv. nickel
v. bromine

1. write the abbreviated electron configuration of the following elements?

i. nitrogen
ii. argon
iii. manganese
iv. silver
v. barium

1. identify the elements from the orbital filling diagrams.

orbital filling diagram element

Explanation:

Step1: Count electrons

For each orbital diagram, count the number of electrons (each arrow represents an electron, with two arrows in an orbital indicating two electrons).

Step2: Relate to atomic number

The number of electrons in a neutral atom is equal to its atomic number. Use the periodic table to identify the element with that atomic number.

• First diagram: \(1s^22s^22p^1\), total electrons \(= 2 + 2+1=5\). Boron (\(B\)) has atomic number \(5\).
• Second diagram: \(1s^22s^22p^63s^23p^3\), total electrons \(=2 + 2+6 + 2+3 = 15\). Phosphorus (\(P\)) has atomic number \(15\).
• Third diagram: \(1s^22s^22p^63s^23p^5\), total electrons \(=2 + 2+6 + 2+5 = 17\). Chlorine (\(Cl\)) has atomic number \(17\).
• Fourth diagram: \(1s^22s^22p^63s^23p^64s^23d^5\), total electrons \(=2+2 + 6+2+6 + 2+5=25\). Manganese (\(Mn\)) has atomic number \(25\).
• Fifth diagram: \(1s^22s^22p^63s^23p^64s^23d^{10}4p^3\), total electrons \(=2+2 + 6+2+6 + 2+10+3=33\). Arsenic (\(As\)) has atomic number \(33\).

Answer:

Boron (\(B\)), Phosphorus (\(P\)), Chlorine (\(Cl\)), Manganese (\(Mn\)), Arsenic (\(As\))