QUESTION IMAGE
Question
write how many protons, neutrons, and electrons are in the atom. then, draw the atom.
- c^6
12.011
p=
n=
e=
- b^5
10.81
p=
n=
e=
- ne^10
20.180
p=
n=
e=
- h^1
1.008
- li^3
6.94
p=
n=
e=
- be^4
9.0122
p=
n=
e=
- n^7
14.007
p=
n=
e=
- o^8
15.999
p=
n=
e=
Step1: Recall atomic number and mass - number concepts
The atomic number (lower - left number, if not given, can be found from the element symbol) is equal to the number of protons ($P$) and the number of electrons ($E$) in a neutral atom. The mass number (upper - left number, or approximated from the atomic mass) minus the atomic number gives the number of neutrons ($N$).
Step2: Analyze carbon (C)
For carbon ($C$), the atomic number is 6. So, $P = 6$, $E=6$. The mass number is approximately 12 (from 12.011), so $N=12 - 6=6$.
Step3: Analyze boron (B)
For boron ($B$), the atomic number is 5. So, $P = 5$, $E = 5$. The mass number is approximately 11 (from 10.81), so $N=11 - 5 = 6$.
Step4: Analyze neon (Ne)
For neon ($Ne$), the atomic number is 10. So, $P = 10$, $E = 10$. The mass number is approximately 20 (from 20.180), so $N=20 - 10=10$.
Step5: Analyze hydrogen (H)
For hydrogen ($H$), the atomic number is 1. So, $P = 1$, $E = 1$. The mass number is approximately 1 (from 1.008), so $N=1 - 1=0$.
Step6: Analyze lithium (Li)
For lithium ($Li$), the atomic number is 3. So, $P = 3$, $E = 3$. The mass number is approximately 7 (from 6.94), so $N=7 - 3=4$.
Step7: Analyze beryllium (Be)
For beryllium ($Be$), the atomic number is 4. So, $P = 4$, $E = 4$. The mass number is approximately 9 (from 9.0122), so $N=9 - 4=5$.
Step8: Analyze nitrogen (N)
For nitrogen ($N$), the atomic number is 7. So, $P = 7$, $E = 7$. The mass number is approximately 14 (from 14.007), so $N=14 - 7=7$.
Step9: Analyze oxygen (O)
For oxygen ($O$), the atomic number is 8. So, $P = 8$, $E = 8$. The mass number is approximately 16 (from 15.999), so $N=16 - 8=8$.
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