Question

1. write the formula for mercury (ii) bromide (0.5 points) *

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1. write the formula for copper (i) oxide (0.5 points) *

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1. write the formula for cobalt (iii) chloride (0.5 points) *

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1. write the formula for lead (iv) oxide (0.5 points) *

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Explanation:

Step1: Determine the ions

• Mercury (II) has a charge of \(Hg^{2+}\), bromide has a charge of \(Br^{-}\).
• Copper (I) has a charge of \(Cu^{+}\), oxide has a charge of \(O^{2 -}\).
• Cobalt (III) has a charge of \(Co^{3+}\), chloride has a charge of \(Cl^{-}\).
• Lead (IV) has a charge of \(Pb^{4+}\), oxide has a charge of \(O^{2 -}\).

Step2: Balance the charges

• For \(Hg^{2+}\) and \(Br^{-}\): To balance the charge, we need 2 \(Br^{-}\) ions for each \(Hg^{2+}\) ion.
• For \(Cu^{+}\) and \(O^{2 -}\): To balance the charge, we need 2 \(Cu^{+}\) ions for each \(O^{2 -}\) ion.
• For \(Co^{3+}\) and \(Cl^{-}\): To balance the charge, we need 3 \(Cl^{-}\) ions for each \(Co^{3+}\) ion.
• For \(Pb^{4+}\) and \(O^{2 -}\): To balance the charge, we need 2 \(O^{2 -}\) ions for each \(Pb^{4+}\) ion.

Answer:

1. \(HgBr_{2}\)
2. \(Cu_{2}O\)
3. \(CoCl_{3}\)
4. \(PbO_{2}\)