Question

write the equilibrium constant expression for this reaction:

ch₃cl(aq) + oh⁻(aq) → ch₃oh(aq) + cl⁻(aq)

Explanation:

Step1: Recall equilibrium constant formula

For reaction \(aA + bB
ightleftharpoons cC + dD\), \(K=\frac{[C]^c[D]^d}{[A]^a[B]^b}\)

Step2: Identify reactants and products

Reactants: \(\text{CH}_3\text{Cl}\), \(\text{OH}^-\); Products: \(\text{CH}_3\text{OH}\), \(\text{Cl}^-\)

Step3: Apply formula

All coefficients \(a = b = c = d=1\), so \(K = \frac{[\text{CH}_3\text{OH}][\text{Cl}^-]}{[\text{CH}_3\text{Cl}][\text{OH}^-]}\)

Answer:

$$K = \frac{[\text{CH}_3\text{OH}][\text{Cl}^-]}{[\text{CH}_3\text{Cl}][\text{OH}^-]}$$