Question

write an equation in general form of the circle with the given properties.

center at the origin; \\(r = 4\\)

Explanation:

Identify standard form of the circle

$$ (x - h)^2 + (y - k)^2 = r^2 $$

$$ (h, k) = (0, 0),\quad r = 4 $$

$$ x^2 + y^2 = 16 $$

Convert to general form

$$ x^2 + y^2 - 16 = 0 $$

Answer:

Write an equation in general form of the circle with the given properties.

Center at the origin; \(r = 4\)

<blank>\(x^2 + y^2 - 16 = 0\)</blank>