Question

1. write the electron configuration and abbreviated electron configurations of the following elements: a. fluorine b. aluminum

Explanation:

Step1: Determine the atomic number of fluorine

Fluorine has an atomic number of \(9\).

Step2: Write the electron configuration of fluorine

Using the Aufbau principle, the electron configuration is \(1s^{2}2s^{2}2p^{5}\).

Step3: Write the abbreviated electron configuration of fluorine

The noble gas before fluorine is helium (\(He\)), so the abbreviated configuration is \([He]2s^{2}2p^{5}\).

Step4: Determine the atomic number of aluminum

Aluminum has an atomic number of \(13\).

Step5: Write the electron configuration of aluminum

Using the Aufbau principle, the electron configuration is \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{1}\).

Step6: Write the abbreviated electron configuration of aluminum

The noble gas before aluminum is neon (\(Ne\)), so the abbreviated configuration is \([Ne]3s^{2}3p^{1}\).

Answer:

a. Electron configuration: \(1s^{2}2s^{2}2p^{5}\); Abbreviated electron configuration: \([He]2s^{2}2p^{5}\)
b. Electron configuration: \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{1}\); Abbreviated electron configuration: \([Ne]3s^{2}3p^{1}\)