Question

write the complete ground - state electron configuration of cs^+
for multi - digit superscripts or coefficients, use each number in succession.

Explanation:

Step1: Determine the atomic number of Cs

Cesium (Cs) has an atomic number of 55. The \(Cs^{+}\) ion has lost one electron, so it has 54 electrons.

Step2: Write the electron configuration

Using the Aufbau principle, the electron configuration of \(Cs^{+}\) is \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{6}5s^{2}4d^{10}5p^{6}\)

Answer:

\(1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{6}5s^{2}4d^{10}5p^{6}\)