Question

write the complete ground - state electron configuration of al. for multi - digit superscripts or coefficients, use each number in succession

Explanation:

Step1: Determine the atomic number of Al

Aluminum (Al) has an atomic number of \(13\). This means it has \(13\) electrons in its neutral state.

Step2: Fill the orbitals according to the Aufbau principle

• The \(1s\) orbital can hold \(2\) electrons: \(1s^{2}\)
• The \(2s\) orbital can hold \(2\) electrons: \(2s^{2}\)
• The \(2p\) orbital can hold \(6\) electrons: \(2p^{6}\)
• The \(3s\) orbital can hold \(2\) electrons: \(3s^{2}\)
• After filling \(3s\), we have \(13-(2 + 2+6 + 2)=1\) electron left. This electron goes into the \(3p\) orbital: \(3p^{1}\)

Answer:

\(1s^{2}2s^{2}2p^{6}3s^{2}3p^{1}\)