Question

which type of bonding involves sharing valence electrons, but the valence electrons arent confined to a specific region between atoms and instead exist throughout the crystal structure of the material?
a) ionic bonding
b) covalent bonding
c) polar covalent bonding
d) metallic bonding
question 10 (5 points)
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will sodium iodide react with bromine to produce sodium bromide and iodine? why or why not?
a) no, because bromine has lower activity than iodine
b) no, because bromine has higher activity than iodine

Explanation:

For the first question:

• Ionic bonding involves transfer of electrons.
• Covalent bonding (including polar covalent) has electrons shared between specific atoms.
• Metallic bonding has delocalized valence electrons (not confined to a specific region between atoms) throughout the crystal structure.

For the second question:

• In a single - displacement reaction (halogen - halogen displacement), a more active halogen can displace a less active halogen from its salt.
• The activity order of halogens is \(F_2>Cl_2 > Br_2> I_2\). Bromine (\(Br_2\)) is more active than iodine (\(I_2\)). So, bromine can displace iodine from sodium iodide (\(NaI\)): \(2NaI + Br_2=2NaBr + I_2\). The options provided for the second question seem to have an error in the reasoning in the options (maybe a mis - type in the option labels as the reaction should occur). But if we consider the general concept of halogen activity.

Answer:

First question: D. Metallic bonding
Second question: (Assuming the correct reaction occurs based on halogen activity, but if we follow the option structure, there is an error. However, if we consider the activity concept) The reaction will occur because bromine has higher activity than iodine. But if we have to choose from the given options (assuming a mis - label in options), there is an inconsistency. But if we consider the first - level analysis of halogen activity for the reaction \(2NaI+Br_2 = 2NaBr + I_2\) (a single - displacement reaction where a more active halogen displaces a less active one from its salt)