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which of these numbers are solutions of $n^2 = 64$? choose two correct …

Question

which of these numbers are solutions of $n^2 = 64$? choose two correct answers. $-12$ $-8$ $-6$ $6$ $8$ $12$

Explanation:

Step1: Solve the equation \(n^2 = 64\)

To find the solutions, we take the square root of both sides. Remember that \(\sqrt{x^2}=\pm x\), so \(n=\pm\sqrt{64}\).

Step2: Calculate the square root of 64

We know that \(\sqrt{64} = 8\), so the solutions are \(n = 8\) and \(n=-8\) (because \((-8)^2=(-8)\times(-8) = 64\) and \(8^2 = 8\times8=64\)).

Answer:

B. \(-8\), D. \(8\) (Note: Here we assume the options are labeled as follows for clarity: A. \(-12\), B. \(-8\), C. \(-6\), D. \(6\), E. \(8\), F. \(12\). So the correct answers are B. \(-8\) and E. \(8\))