Question

which statement correctly describes the oxidation number of the manganese atom (mn) in mni₂ and mno₂? (1 point) manganese has an oxidation number of +2 in mni₂ +4 and mno₂. manganese has an oxidation number of +4 in both mni₂ and mno₂. manganese has an oxidation number of +2 in both mni₂ and mno₂.

Explanation:

Step1: Oxidation number of \(I\) and \(O\)

The oxidation number of \(I\) (iodine) in \(MnI_{2}\) is \(- 1\), and the oxidation number of \(O\) (oxygen) in \(MnO_{2}\) is \(-2\).

Step2: Calculate oxidation number of \(Mn\) in \(MnI_{2}\)

Let the oxidation number of \(Mn\) be \(x\). For \(MnI_{2}\), using the rule that the sum of oxidation numbers in a compound is \(0\): \(x + 2\times(-1)=0\). Solving for \(x\): \(x-2 = 0\), so \(x = + 2\).

Step3: Calculate oxidation number of \(Mn\) in \(MnO_{2}\)

Let the oxidation number of \(Mn\) be \(y\). For \(MnO_{2}\), using the rule that the sum of oxidation numbers in a compound is \(0\): \(y+2\times(-2)=0\). Solving for \(y\): \(y - 4=0\), so \(y=+4\).

Answer:

Manganese has an oxidation number of \(+2\) in \(MnI_{2}\) and \(+4\) in \(MnO_{2}\).