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which point is in quadrant ii? (-2, 2) (2, 5) (5, -1) (-1, -1)

Question

which point is in quadrant ii? (-2, 2) (2, 5) (5, -1) (-1, -1)

Explanation:

Step1: Recall quadrant rules

In a coordinate system:

  • Quadrant I: \(x>0,y>0\)
  • Quadrant II: \(x < 0,y>0\)
  • Quadrant III: \(x < 0,y < 0\)
  • Quadrant IV: \(x>0,y < 0\)

Step2: Analyze each point

  • For \((-2,2)\): \(x=-2<0,y = 2>0\), so it is in Quadrant II.
  • For \((2,5)\): \(x = 2>0,y=5>0\), so it is in Quadrant I.
  • For \((5,-1)\): \(x = 5>0,y=-1<0\), so it is in Quadrant IV.
  • For \((-1,-1)\): \(x=-1<0,y=-1<0\), so it is in Quadrant III.

Answer:

\((-2, 2)\)