QUESTION IMAGE
Question
which of the numbers below are some potential roots of (p(x) = x^3 + 6x^2 - 7x - 60) according to the rational root theorem?
-10
-7
-5
3
15
24
use synthetic division to test one potential root. enter the numbers that complete the division problem.
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(a = \\)
(b = \\)
(c = \\)
(d = \\)
🆕 New Concept Discovered: Rational Root Theorem & Synthetic Division
Finding possible rational roots and testing them using synthetic division.
Step 1: Find potential roots using the Rational Root Theorem
According to the Rational Root Theorem, any potential rational root of the polynomial \( p(x) = a_n x^n + \dots + a_0 \) must be of the form \( \frac{p}{q} \), where:
- \( p \) is a factor of the constant term \( a_0 = -60 \)
- \( q \) is a factor of the leading coefficient \( a_n = 1 \)
Since the leading coefficient is \( 1 \), the potential rational roots are simply the integer factors of \( -60 \).
Let's list the factors of \( 60 \):
\[ \pm 1, \pm 2, \pm 3, \pm 4, \pm 5, \pm 6, \pm 10, \pm 12, \pm 15, \pm 20, \pm 30, \pm 60 \]
Now we check which of the given options are in this list:
- \( -10 \): Yes (factor of \( -60 \))
- \( -7 \): No
- \( -5 \): Yes (factor of \( -60 \))
- \( 3 \): Yes (factor of \( -60 \))
- \( 15 \): Yes (factor of \( -60 \))
- \( 24 \): No
Step 2: Complete the synthetic division
We are testing the potential root \( -5 \) using synthetic division for the polynomial \( p(x) = 1x^3 + 6x^2 - 7x - 60 \).
The setup is:
-5 | 1 6 -7 -60
| a c 60
---------------------
1 b d 0
Let's perform the steps of synthetic division:
- Bring down the first coefficient: \( 1 \).
- Multiply \( -5 \) by \( 1 \) to get \( a \):
\[ a = -5 \times 1 = -5 \]
- Add the second column to get \( b \):
\[ b = 6 + a = 6 + (-5) = 1 \]
- Multiply \( -5 \) by \( b \) to get \( c \):
\[ c = -5 \times 1 = -5 \]
- Add the third column to get \( d \):
\[ d = -7 + c = -7 + (-5) = -12 \]
- Multiply \( -5 \) by \( d \) to verify the next value:
\[ -5 \times (-12) = 60 \] (This matches the given value in the table)
- Add the last column:
\[ -60 + 60 = 0 \]
Thus, the missing values are:
- \( a = -5 \)
- \( b = 1 \)
- \( c = -5 \)
- \( d = -12 \)
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Part 1: Potential Roots
The potential roots of \( p(x) \) from the given list are:
- \( -10 \)
- \( -5 \)
- \( 3 \)
- \( 15 \)
Part 2: Synthetic Division Values
- \( a = -5 \)
- \( b = 1 \)
- \( c = -5 \)
- \( d = -12 \)