Question

which graph shows a translation 6 units left from the parallelogram abcd to the parallelogram abcd?

Explanation:

Step1: Recall Translation Rule

A translation 6 units left means subtracting 6 from the x - coordinate of each vertex of the original parallelogram \(ABCD\) to get the coordinates of \(A'B'C'D'\).

Step2: Analyze Each Graph

• For the first graph: Check the horizontal distance between corresponding vertices (e.g., \(A\) and \(A'\)). The distance does not seem to be 6 units.
• For the second graph: The horizontal shift between \(ABCD\) (red) and \(A'B'C'D'\) (blue) is not 6 units.
• For the third graph: Let's assume the original parallelogram \(ABCD\) (red) has vertices with x - coordinates, and after shifting 6 units left, the new vertices \(A'B'C'D'\) (blue) should have x - coordinates that are 6 less. By visually inspecting the grid, the horizontal distance between corresponding vertices is 6 units (since moving from the red parallelogram to the blue parallelogram, each point moves 6 units to the left).

Answer:

The Right Graph (the third graph from the left)