Question

which of the following measurements does not have four significant figures?
760.2 mm hg
0.022 g
298.0 k
314.5 ml
question 3 (1 point)
calculate the answer to the following with appropriate significant figures.
3.56 - 4.321 + 5.9486 = ?
5.1876
5.18
5.2
5.19
5.188

Explanation:

Step1: Count significant figures

• For \(760.2\) mm Hg: Non - zero digits and the zero between non - zero digits are significant. So, it has \(4\) significant figures.
• For \(0.022\) g: Leading zeros are not significant. So, it has \(2\) significant figures.
• For \(298.0\) K: Trailing zero after the decimal is significant. So, it has \(4\) significant figures.
• For \(314.5\) mL: All non - zero digits are significant. So, it has \(4\) significant figures.

Step2: Calculate the arithmetic operation

$$
LATEXBLOCK0
$$

• In addition and subtraction, the result should be rounded to the least number of decimal places. \(3.56\) has two decimal places, \(4.321\) has three decimal places, and \(5.9486\) has four decimal places. We round to two decimal places. So, \(5.1876\approx5.19\)

Answer:

• The measurement that does not have four significant figures is \(0.022\) g.
• The result of \(3.56 - 4.321+5.9486\) with appropriate significant figures is \(5.19\)